X^2+0.0018x-0.0018=0

Solution for X^2+0.0018x-0.0018=0 equation:

X^2+0.0018X-0.0018=0

a = 1; b = 0.0018; c = -0.0018;
Δ = b2-4ac
Δ = 0.00182-4·1·(-0.0018)
Δ = 0.00720324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0018)-\sqrt{0.00720324}}{2*1}=\frac{-0.0018-\sqrt{0.00720324}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0018)+\sqrt{0.00720324}}{2*1}=\frac{-0.0018+\sqrt{0.00720324}}{2}
$